Bunuel wrote:
gmatbull wrote:
A closed aluminum rectangular box has inner dimensions x centimeters by y centimeters by z centimeters. Each of the six sides of the box is 1 centimeter thick. Calculate the volume of the aluminium, in cubic centimeters?
A. xyz + 8
B. 2(xy + xz + yz + 4)
C. 2(xy + xz + yz) – xyz
D. 2(xy + xz + yz + x + y + z + 4)
E. 2(xy + xz + yz + 2x + 2y + 2z + 4)
Are we really concerned with the extra 1cm thickness in calculating the volume? The thickness does not
be filled; so, howA. xyz + 8
B. 2(xy + xz + yz + 4)
C. 2(xy + xz + yz) – xyz
D. 2(xy + xz + yz + x + y + z + 4)
E. 2(xy + xz + yz + 2x + 2y + 2z + 4)
Are we really concerned with the extra 1cm thickness in calculating the volume? The thickness does not
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