Bunuel wrote:
Which of the following is equivalent to\((\frac{1}{3})^{-4}*(\frac{1}{9})^{-3}*(\frac{1}{27})^{-2}\) ?
A.\((\frac{1}{3})^{-8}\)
B.\((\frac{1}{3})^{-9}\)
C.\((\frac{1}{3})^{-16}\)
D.\((\frac{1}{3})^{-18}\)
E.\((\frac{1}{3})^{-144}\)
Kudos for a correct solution.
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