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Problem Solving (PS) | If x^2 - 2*2^(1/2)*x = -2, then x^2 =

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0
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Bunuel wrote:

If \(x^2 - 2\sqrt{2}*x = -2\), then \(x^2 =\)

A. -1
B. 1
C. 2
D. 4
E. 0

\(x^2 - 2\sqrt{2}*x = -2\)

\(x^2 - 2\sqrt{2}x + 2 = 0\)

Factor the expression:

\((x -
\sqrt{2})(x -
\sqrt{2}) = 0\)

\(x = \sqrt{2}\)

\(x^2 = 2\)
...

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