"Assume once the house gets build, they will stop working"
A will keep building the house while B breaks it the next day. Therefore, when A finally completes the house, "they will stop working". Thus, B will be working one day less than A eventually as shownbelow:
Make,Break,Make,Break...Make,Break,MAKE
Equation:
Work of A - Work of B = 1
[1/20 x T] -[1/30 x (t-1)] = 1
Solve for T (A's days) -> 58
Calculate T-1 (B's days) -> 57
Total days for house to be built = 58 + 57 = 115
...
A will keep building the house while B breaks it the next day. Therefore, when A finally completes the house, "they will stop working". Thus, B will be working one day less than A eventually as shownbelow:
Make,Break,Make,Break...Make,Break,MAKE
Equation:
Work of A - Work of B = 1
[1/20 x T] -[1/30 x (t-1)] = 1
Solve for T (A's days) -> 58
Calculate T-1 (B's days) -> 57
Total days for house to be built = 58 + 57 = 115
...
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