Problem Solving (PS) | 4 < x^2 + 2x + 1 < 16

hi..

so lets solve the equation..
\(4 < x^2 + 2x + 1 < 16......4<(x+1)^2<16......\)
we are looking for integer values..
(x+1) can take two values (x+1)=3 or x+1=-3......
so x=3-1=2 and x=-3-1=-4

so two values : 2 and -4
C

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