Hi, answer must be E.
As z^2 - 4z > 5
=> z^2 - 4z - 5 > 0
(z - 5)(z + 1) > 0
when -1 < z < 5, (z-5)(z+1) < 0 always
when z = -1 or 5, (z-5)(z+1) = 0
when z < -1 or z > 5, then (z-5)(z+1) > 0 always
since none of the options match z < -1 or z > 5, answer must be E
As z^2 - 4z > 5
=> z^2 - 4z - 5 > 0
(z - 5)(z + 1) > 0
when -1 < z < 5, (z-5)(z+1) < 0 always
when z = -1 or 5, (z-5)(z+1) = 0
when z < -1 or z > 5, then (z-5)(z+1) > 0 always
since none of the options match z < -1 or z > 5, answer must be E
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